Related Post: X 3 5 0 2 X 3 5 2x 0 X 3 5 1 2 0 4 X 3 Y 4 5 0 2x Y 10 X 3 2x 5 0 By Regula Falsi Method X 3 2x 5 0 By Newton Raphson Method X 3 2x 5 0 By Iteration Method X 3 2x 5 0 By Bisection Method X 3 2x 5 0 Using Secant Method X 3 2 Y 5 2 0