Related Post: X 3 1 X 2 0 X3 X 1 )( X 2 0 ( X 3 - 1 X - 2 ≥ 0 3 X 1 4 X 2 0 X 3 X 2 1 0 By Iteration Method X 3 X 2 1 0 By Bisection Method X 3 X 2 1 0 Solution 2x 3 )( X 3 )( X 1 2 = 0 X 1 3 X 1 6 2 0 X 5 )( 2x 3 )/( X 1 2 = 0